http://www.perlmonks.org?node_id=1055202

Lennotoecom has asked for the wisdom of the Perl Monks concerning the following question:

Hi, can you explain please
how exactly this snippet works,
and if possible context transformation:
@a = qw(a b c d e); $b = () = @a; # $b now is 5
Thanks!

update:
$b = @a;
would do the same effect,
so basically there is no need for ();
but still, the question remains if someone got
any explanation

update update:
thank you for answer Mr. Choroba
yes indeed that was just the wrong example that was used by some fellow
your last example was helpful
thank a lot

Replies are listed 'Best First'.
Re: need an explanation
by choroba (Cardinal) on Sep 22, 2013 at 21:55 UTC
    The first line is equivalent to
    @a = ('a', 'b', 'c', 'd', 'e');

    qw just "quotes words".

    The second line is usually written as

    $b = @a;

    or, for more clarity,

    $b = scalar @a;

    Perl is sensitive to context. By assigning to a scalar value, you impose the scalar context on the right hand side of the assignment. Arrays return their size (number of elements) in scalar context. Using = () = here has no effect and is only confusing. Update: It is usually used to force list context, for example

    $x = () = "abcdABCabA" =~ /a/ig; # Count A's regardless of case.
    لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ