in reply to Re^2: A "but" operator.
in thread A "but" operator.
In your analogy, but can't be XOR, it's ($A and !$B). XOR is ($A and !$B) || (!$A and $B). Or equivalently, but could be "A and (A XOR B)", if you prefer to keep it complicated and silly, in a Lewis Caroll (sp?) sort of way.
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