in reply to query about perl
Try print $ARGV[0].
Addendum:
Extracted from perlvar
@ARGV The array @ARGV contains the command-line arguments intended for the s +cript. $#ARGV is generally the number of arguments minus one, because + $ARGV[0] is the first argument, not the program's command name itsel +f. See $0 for the command name.
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In Section
Seekers of Perl Wisdom