in reply to Operator Precedence
"I noticed an interesting thing in doing this. Usually you
don't need to use brackets at all. The precedence table was
designed in a clever way so that most of the time if you
are writing your code clearly, you don't need to change
precedence at all by using brackets."
That's usually true, but then shouldn't $f ^ $g == 1 be equivalent to ($f ^ $g) == 1?
In Section
Meditations