Join a file piped to a perl script

tradez has asked for the wisdom of the Perl Monks concerning the following question:

Fellow Monks, I recently needed to write some code to join a file piped to a perl script. Rather then coding the whole

my $file = $argv[0];
open (MYFILE, "$argv[0]");
while(<MYFILE){
.....
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I remembered there being a special perl way of handling files piped to a script. a $_ type thing ( special character) that fills a data structure with the array for you, saving me precious key strokes. Please inform.

Tradez
"Never underestimate the predicability of stupidity"
- Bullet Tooth Tony, Snatch (2001)
Edit kudra, 2002-04-15 Changed title
Comment on Join a file piped to a perl script
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Re: Lazy Coder by dws (Chancellor) on Apr 12, 2002 at 20:27 UTC
open (MYFILE, "$argv[0]"); Unless this script is for controlled use, you might consider untainting `$argv[0]` before using it. Otherwise, you risk having a day ruined when some lamer passes `'rm -rf * \|'` as an argument.	[reply] [d/l] [select]
Re: Lazy Coder by Zaxo (Archbishop) on Apr 12, 2002 at 20:11 UTC
You may be looking for the diamond operator, `<>`. see perldoc perlop. After Compline, Zaxo	[reply]
Re^2: Lazy Coder by tadman (Prior) on Apr 13, 2002 at 00:10 UTC
Lazy in a good way: `my $input = join ('', <>);` Or, if you prefer named arguments: `my $input = open (IN, $ARGV[0]) && join ('', <IN>);` Don't forget that it's `@ARGV` and not `@argv`. If you're using this as a CGI application, it virtually, but not entirely, goes without saying: `use CGI;`	[reply] [d/l] [select]
False lazyness by Fletch (Bishop) on Apr 12, 2002 at 19:54 UTC
`perldoc perlopentut`, `perldoc -f open`	[reply] [d/l] [select]
Re: False lazyness by tradez (Pilgrim) on Apr 12, 2002 at 21:42 UTC
Not really what I was going for, i meant if like prompt$:./perlscript.pl somefile was ran. Tradez "Never underestimate the predicability of stupidity" - Bullet Tooth Tony, Snatch (2001)	[reply]

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