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Re^2: efficient determination of in/out of hours

by Random_Walk (Prior)
on Oct 17, 2013 at 15:45 UTC ( [id://1058639]=note: print w/replies, xml ) Need Help??

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  1. or download this
    my $now = time;
my $today = $now - ($now % 86400);
...
    ...
}
...
  2. or download this
    start of day (epoch based):Thu Oct 17 01:00:00 2013
Bank Hols
Mon Oct 21 00:00:00 2013
Mon Feb  3 00:00:00 2014

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