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Re: Quirky regex bug

by Corion (Pope)
on Jan 07, 2002 at 02:35 UTC ( #136721=note: print w/replies, xml ) Need Help??

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  1. or download this
    print $1 if 'abcfoobc' =~ /(.*)foo\1/; # works
    print $1 if 'abcfoobc' =~ /(.*).{3}\1/; # does work, $1 empty
    print $1 if 'abcfoobc' =~ /(.+)foo\1/; # works as well
    
  2. or download this
    print $1 if 'abcfoobc' =~ /(.*)\w*\1/; # does work
    
  3. or download this
    perl -MHTTP::Daemon -MHTTP::Response -MLWP::Simple -e ' ;    # The  
    $d = new HTTP::Daemon and fork and getprint $d->url and exit;#spider
    ($c = $d->accept())->get_request(); $c->send_response( new   #in the
    HTTP::Response(200,$_,$_,qq(Just another Perl hacker\n))); ' #  web 
    

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[Corion]: oiskuu: Depends on what you want to do with that information
[tye]: I'm not depending on that feature. But I could in this environment. I'm using getlogin(). shrug
[Corion]: For benign logging (which user started this DB instance), it's OK
[tye]: We use auditd for security monitoring. So we can rely on auditing being enabled. I'm not sure who would want to not be able to audit. Maybe some VM inside another system with audit?
[SuicideJunkie]: spies would want a system to not be able to audit.

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