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# We're hunting the (properly bracketed)
$str =~ # 'm \d+' occurrences. They must be
(?:m \s \d+ \s)* # Any number of m \d+ groups.
bar)/xg; # Finally terminated with bar (though not
# necessarily the end of string.)
- starts at the current 'beginning' of the string
- matches the 'm \d+' at the current position
- matches (aft) all the remaining 'm \d+' and the final bar
- and THROWS AWAY the fore and aft matches (they're non-capturi
Once (shame on you!)
Twice (shame on me!)
More often than I'd like to be
All the time
Just when answering stupid polls
Who you callin' a fool?
I refuse to vote in this ridiculous poll
Results (540 votes). Check out past polls.