note
nonsequitur
<p>This may be OT since it doesn't really have anything to do with Perl,
but one of your original assumptions is wrong.</p>
<p>In an even base a integer ending in an even digit must be even because
the previous digits are multiplied by a power of an even base .
Leaving the last digit to decide the parity.</p>
<p>In an odd base the total of the digits must be even for the integer to
be even because all of the digits are multiplied by a power of an odd base so
that the that the parity of the integer depends on parity of all the digits.</p>
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