note tedv I don't think it's that different. It's just a weighting problem with a threshold. Give each node a weight and divide by distance and you have a rough heuristic for how important it is to get there. Choose an appropriate threshold and you've reduced it to the TSP. In theory, a slightly better solution is to make a large graph and weight entire sections of the graph (ie. groups of nodes). This tells you that 9 average nodes are better than 1 great node and 8 worthless ones. But that's just another way of simplifying N nodes into 1 node, and you still have to apply a heuristical threshold to end up with a the TSP again. <BR><BR>-Ted 40586 40591