note
tedv
I don't think it's that different. It's just a weighting
problem with a threshold. Give each node a weight and
divide by distance and you have a rough heuristic for how
important it is to get there. Choose an appropriate threshold
and you've reduced it to the TSP. In theory, a slightly better
solution is to make a large graph and weight entire sections
of the graph (ie. groups of nodes). This tells you that 9
average nodes are better than 1 great node and 8 worthless ones.
But that's just another way of simplifying N nodes into 1 node,
and you still have to apply a heuristical threshold to end up
with a the TSP again.
<BR><BR>-Ted
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