categorized question QandAEditors array order superset This is an attempt to save a thread in SoPW which I thought can be useful for others.<br><br> There are already incredible answers in the thread, so feel free to check in SoPW.<br> Please don't misunderstand me. I honestly think this can be useful. I don't mean to boost my XP here, or in that thread which I posted.<br><br> Here I wanted to test if an array is of a _same order_ with another, left array is always be greater/superset or equal to the right one. Here is my current code.<br> <code> #!/usr/bin/perl -w # The original code here is constructed # thanks to ysth's suggestion use strict; my @AR = qw(a b c); # First Case my @ar = qw(z a b c); # Second Case my @ar2 = qw(b a); my @ar3 = qw(a b); my @ar4 = qw(a b c); my @ar5 = qw(z a b c); print "First case\n"; # L R print test_ordered(\@ar,\@ar2),"\n"; # Answer:False(0) print test_ordered(\@ar,\@ar3),"\n"; # Answer:True(1) print test_ordered(\@ar,\@ar4),"\n"; # Answer:True(1) print test_ordered(\@ar,\@ar5),"\n"; # Answer:True(1) print "Second case\n"; print test_ordered(\@AR,\@ar2),"\n"; # Answer: False(0) print test_ordered(\@AR,\@ar3),"\n"; # Answer: True(1) print test_ordered(\@AR,\@ar4),"\n"; # Answer: True(1) sub test_ordered { #test if two arrays are ordered in same way #assuming no duplicate and left array is always #be greater/superset or equal to the right one # L R my ($ar1,$ar2)= @_; my %h; @h{@$ar1} = (0..$#{$ar1}); my $decision = grep($h{$ar2[$_]} != $_, 0..$#{$ar2}) ? 0 : 1; return $decision; } </code> Currently the code give correct answer for the Second Case. How can I modify it such that it's also correct for the First Case?<br> Now it prints: <code> First Case: Second Case: 0 0 0 1 0 1 1 </code> The desired answer is: <code> First Case: Second Case: 0 0 1 1 1 1 1 </code> <div class="pmsig"><div class="pmsig-393886"> Regards,<br> Edward </div></div> <code> 1824