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Re^3: How to call a sub-routine ref

by BrowserUk (Pope)
on Oct 19, 2012 at 20:52 UTC ( #1000043=note: print w/ replies, xml ) Need Help??


in reply to Re^2: How to call a sub-routine ref
in thread How to call a sub-routine ref

For that particular case, you don't need either the -> or the &{}:

sub x{ say "x got [ @_ ]"; };; $h{x} = \&x;; $href = \%h;; $href->{x}('fred','bill');; x got [ fred bill ]

With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.

RIP Neil Armstrong


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