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Re^2: ~~ and list literal

by Anonymous Monk
on Oct 25, 2012 at 23:46 UTC ( #1000967=note: print w/ replies, xml ) Need Help??


in reply to Re: ~~ and list literal
in thread ~~ and list literal

Follow-up question:

Why does "x" ~~ "a", "b", "c" always give 1? Running through Deparse gives: 'x' ~~ 'a', '???', 'c'. What is going on here?

And why does "x" ~~ sub { "a", "b", "c" } also give 1? Smart match is giving me a headache...


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Re^3: ~~ and list literal
by mbethke (Hermit) on Oct 26, 2012 at 01:56 UTC

    With the ~~ operator having much higher precedence than the comma, this is parsed as a comma-list of a smart-match whose result doesn't matter, more stuff that doesn't matter at all, and "c" which is true.

    The second one would pass "x" to the sub which again evaluates a comma-list and throws away everything (including the argument) but "c" which gets returned and is true.

Re^3: ~~ and list literal
by Anonymous Monk on Oct 26, 2012 at 03:16 UTC

    ...

    Because of precedence/binding

    Consider

    $ perl -le " $f = 1,2,3 ; print $f" 1 $ perl -MO=Deparse -le " $f = 1,2,3 ; print $f" BEGIN { $/ = "\n"; $\ = "\n"; } $f = 1, '???', '???'; print $f; -e syntax OK

    Compare it to

    $ perl -le " $f = ( 1,2,3 ); print $f" 3 $ perl -MO=Deparse -le " $f = ( 1,2,3 ) ; print $f" BEGIN { $/ = "\n"; $\ = "\n"; } $f = ('???', '???', 3); print $f; -e syntax OK

    Since smart is binary (like = in the above example), it works on two scalars, left-scalar operator right-scalar

    If you have no parentheses, the first scalar is taken, the closest, because assignment operator (=) has higher precedence than comma opeartor (it binds tighter).

    If you add parenthesis, then you have the fabled List in Scalar Context, then the comma operator return the last right item (rightest most)

    See Tutorials: Precedence for Idiots

    Since you're confused about precedence you're probably also confused about context, so see Tutorials: Context in Perl: Context tutorial, "List" Is a Four-Letter Word, Easy Reference for Contexts

    Smart match is giving me a headache...

    Stop using it :) worked for me :) Smart-match

Re^3: ~~ and list literal
by ikegami (Pope) on Oct 27, 2012 at 00:15 UTC

    Why does "x" ~~ "a", "b", "c" always give 1?

    It doesn't; it evaluates to "c".

    "," is a very low precedence operator. "x" ~~ "a", "b", "c" means ("x" ~~ "a"), "b", "c", which evaluates to "c" in scalar context.

    And why does "x" ~~ sub { "a", "b", "c" } also give 1?

    It doesn't; it evaluates to "c".

    "x" ~~ sub { "a", "b", "c" } is the same as scalar( sub { "a", "b", "c" }->($x) ). Since  "a", "b", "c" evaluates to "c" in scalar context, that is what is returned.

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