in reply to Random generator fail
But always get between 0 and 1. Any ideas?
Works as designed.
$ perl e 'use 5.10.0; say int(6*rand())+1 foreach(1..10);'
6
5
4
6
2
2
4
6
3
5
Is that what you were after? Or at least something like it?
As MidLifeXis pointed out:
rand EXPR
rand Returns a random fractional number greater than or equa
+l to 0
and less than the value of EXPR. (EXPR should be posit
+ive.)
If EXPR is omitted, the value 1 is used. Currently EXP
+R with
the value 0 is also specialcased as 1 (this was undocu
+mented
before Perl 5.8.0 and is subject to change in future ve
+rsions
of Perl). Automatically calls "srand" unless "srand" h
+as
already been called. See also "srand".
Apply "int()" to the value returned by "rand()" if you
+want
random integers instead of random fractional numbers.
+For
example,
int(rand(10))
returns a random integer between 0 and 9, inclusive.
(Note: If your rand function consistently returns numbe
+rs that
are too large or too small, then your version of Perl w
+as
probably compiled with the wrong number of RANDBITS.)
"rand()" is not cryptographically secure. You should n
+ot rely
on it in securitysensitive situations. As of this wri
+ting, a
number of thirdparty CPAN modules offer random number
generators intended by their authors to be cryptographi
+cally
secure, including: Math::Random::Secure,
Math::Random::MT::Perl, and Math::TrulyRandom.
Peter L. Berghold  Unix Professional
Peter at Berghold dot Net; AOL IM redcowdawg Yahoo IM: blue_cowdawg
Re^2: Random generator fail by Anonymous Monk on Dec 05, 2012 at 22:41 UTC 
Thanks guys. I will take this as work around. But I should not be forced to use random integers, when I want decimals.
Nowhere in documentation it says that rand be conditioned to return integers.
Thank you.
 [reply] 

Have you read the reply? In case you have not, I am repeating the part you missed:
Apply "int()" to the value returned by "rand()" if you want random integers instead of random fractional numbers
No one forces you.
 [reply] 

Please note that rand does not use $_ as an input value (which your original code seems to assume).
You are absolutely correct  the documentation for rand does not state that it conditions the results as integers. That is done by the int call around the results of rand.
Please read the fine documentation:
Returns a random fractional number greater than or equal to 0 and less than the value of EXPR. (EXPR should be positive.) If EXPR is omitted, the value 1 is used.
(emphasis added)
Use rand EXPR if you want a value N where 0 <= N < EXPR. If you want an integer value, apply the int function to the results, if you want a floating point number (decimal), don't apply the int function. It appears to me that the rand function meets your stated requirements exactly, if the proper parameters are passed to it.
If you need to scale the value over a range MIN..MAX (possibly even negative), then you want to use something like MIN + rand(abs(MAXMIN)) (beware the boundary conditions  I may be off by one).
See also:
 [reply] [d/l] [select] 
