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Re^2: Find all strings containing "a" characters, that are not followed by "b" characters.

by Not_a_Number (Parson)
on Dec 12, 2012 at 18:18 UTC ( #1008551=note: print w/replies, xml ) Need Help??


in reply to Re: Find all strings containing "a" characters, that are not followed by "b" characters.
in thread Find all strings containing "a" characters, that are not followed by "b" characters.

No :)

See Re^2: Find all strings containing "a" characters, that are not followed by "b" characters. above.

  • Comment on Re^2: Find all strings containing "a" characters, that are not followed by "b" characters.

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Re^3: Find all strings containing "a" characters, that are not followed by "b" characters.
by Kyshtynbai (Acolyte) on Dec 12, 2012 at 19:40 UTC
    If only I'd knew that logic operators like "and" would work with regular expressions! In my Lama book (5th edition) it is written, that they actualy DO NOT work with regexps (or something has messed up in my head :). I'll check it tomorrow, now gonna sleep). Thank you everyone, guys!

      Well, // is m//, the match operator, it is not a regexp :)

      "logical and" works with m//atch operator, not regexp

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[Corion]: But maybe it's also due to that I play with friends, which makes a game more enjoyable anyway ;)
[Corion]: Oh - I released a new version of some module, thanks to a pull request. But I don't consider "update Makefile.PL" and "update author tests" as "writing code" ;-D
[marto]: sounds fun, the opposite of my weekend :P
[Corion]: marto: You wrote Perl? Or did you have to work (and wrote Perl)?
[marto]: the fun part, I had no fun this weekend, very stressful :)
[Corion]: But I feel an introductory talk gestating, working title "Reading CPAN" - how to read module documentation, how to judge a module, how to read the module tests/examples
[Corion]: marto: Ouch :-/ The kids are making trouble?
[Corion]: Meh - food becons, and colleagues are staring at me, talk to you later, sorry!

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