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Re: Variable scope in while loop

by tobyink (Abbot)
on Dec 19, 2012 at 22:19 UTC ( #1009650=note: print w/replies, xml ) Need Help??

in reply to Variable scope in while loop

Basically, each time you say my $variable you get a brand, spanking new variable. So you're reading a number into the $number variable, but then you say my $number and get a brand, spanking new variable, which happens to have undef as it's value.

my $number; $number = 40; my $number; if ($number > 39) { print "bigger than 39\n"; } elsif ($number < 1) { print "smaller than 1\n"; }
perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'

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