Re: Print only if pattern matches

[Athanasius]

in reply to Print only if pattern matches

The script can be re-written so:

#! perl
use strict;
use warnings;

while (my $line = <DATA>)
{
    if ($line =~  / ^ \d+ \| (\d+?) \| /x &&
        $1 == 1                           &&
        $line =~ s{
                     ^
                        (.*\|)*          # $1
                         .*ABC\.pi=
                        ([\d.]+|[\w.]+)* # $2
                         .*ABC\.id=
                        (\d+|[\w.]+)     # $3
                        .*
                     $
                  }
                  {$1$2|$3}sx)
    {
        print "$1$2|$3\n";
    }
}

__DATA__
...

While this “works”, it is dubious: the * quantifier in a regex means match zero or more of the preceeding; in the substitution, do you really want to match zero occurrences of (.*\|) or ([\d.]+|[\w.]+)? If not, use the + quantifier meaning one or more.

Hope that helps,