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Re^6: [OT] Statistics question.by BillKSmith (Monsignor) |
| on Jan 31, 2013 at 21:23 UTC ( [id://1016395]=note: print w/replies, xml ) | Need Help?? |
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It sounds like my method will not help you in this case. I have used it in solving triangles. I want $b=sqrt($c**2-$a**2). The mathematically equivalent statement $b=sqrt(($c+$a)*($c-$a)) allocates almost twice as many bits for the subtraction. Not knowing this simple trick added weeks of effort to my first real FORTRAN program.
Bill
In Section
Seekers of Perl Wisdom
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