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Re: Matching numeric value between two digits

by toolic (Bishop)
on Feb 04, 2013 at 21:37 UTC ( #1017012=note: print w/replies, xml ) Need Help??


in reply to Matching numeric value between two digits

How's this?
use warnings; use strict; for (qw(1 2 3 4 20.5 97 -5)) { if (($_ >= 1) and ($_ <= 75) and (!/\./)) { print "$_ yes\n"; } else { print "$_ no\n"; } } __END__ 1 yes 2 yes 3 yes 4 yes 20.5 no 97 no -5 no

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Re^2: Matching numeric value between two digits
by shadowfox (Sexton) on Feb 04, 2013 at 22:44 UTC
    The code works, just not in my context, which is much the same as mine, it seems to be something with pulling the value from between the keywords and putting it in $1 but that's what I need in this case. Toying a bit more I ended up with this, which works for my need even if a bit clumsy, can anyone shed light on why it needs to be set in a new variable? The same digit check used in the primary check on $1 just won't work for me but this does.
    if ($_ =~ /\something(.*)somethingelse/i){ if (($1 >= 1) and ($1 <= 75)) { $a = $1; if ($a =~ /^\d+$/){ ... } } }

      You weren't doing the check on $1 in your original code.

      if($1 => 1 and $1 <= 75 and /\d{1}-\d{2}/) { ... }

      The /\d{1}-\d{2}/ is done on $_, not $1.

      BTW you could just do the whole-number check right away:

      if ($_ =~ /\something(\d*)somethingelse/i){ if($1 => 1 and $1 <= 75) { ... } }

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[Discipulus]: ovedpo15 A subroutine may be called using an explicit & prefix. The & is optional in modern Perl... see perlsub in docs and search for ampersand
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