|Perl: the Markov chain saw|
Re^3: Entering the land of Perlby 2teez (Priest)
|on Apr 05, 2013 at 03:17 UTC||Need Help??|
and how you eventually used the it like so:
".. But as far as the prototype passing, I was certain that it enforces a pass by reference..."
If I may suggest, you will do well yielding the wisdom of jwkrahn, as regard the usage of prototype for this reason:
When you use a reference prototype, like "\$", "\@", "\%" "...those symbols don't actually say that you must pass in a scalar reference, an array reference, and a hash reference. Rather, they say you must pass in a scalar variable, an array variable, and a hash variable. That means that the compiler insists upon seeing a properly notated variable of the given type, complete with "$", "@", or "%" in that slot. You must not use a backslash. The compiler silently supplies the backslash for you... "
from Far More than Everything You've Ever Wanted to Know about Prototypes in Perl -- by Tom Christiansen
-- by liverpole, under subheading Problems with Reference Prototypes
Hope this helps.
If you tell me, I'll forget.
If you show me, I'll remember.
if you involve me, I'll understand.
--- Author unknown to me