|Perl: the Markov chain saw|
Re^4: RE question; how to insert a digit between const[a-z]*3 && inc[0-9]*3? (sprintf)by taint (Chaplain)
|on Apr 16, 2013 at 16:21 UTC||Need Help??|
Greetings, and thank you for your thoughtful replies.
Actually "abc" is a constant -- all the files in question are prefaced with those same 3 characters.
So in an effort to be more concise;
I need all the files prefaced by abc, to be followed by 4 digits.
The files abc1000.html through abc9000.html, are already there.
Which leaves abc1.html through abc999.html.
I was able to rename all the files by cobbling up a script with the help of
find(1),basename(1),cp(1), and rm(1) via for loop. But those won't help me with
the references to those files within all the files themselves. :(
So, in summary; how on earth can I append a 0 to abc
on all the references to abc100.html - abc999.html? Appending 2, or three
digits to the other references, will have the same solution. So I chose to use
the "hundreds" list for a starting point.
Thanks again for your thoughtful responses.
#!/usr/bin/perl -Tw use perl::always; my $perl_version = "5.12.4"; print $perl_version;