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Re^4: Thoughts on replacing -> with .

by Corion (Pope)
on Jun 12, 2013 at 11:32 UTC ( #1038437=note: print w/ replies, xml ) Need Help??


in reply to Re^3: Thoughts on replacing -> with .
in thread Thoughts on replacing -> with .

It is like += and .=, which modify the left-hand side by the right hand side.

$a += $b adds the right hand side ($b) to the left hand side, $a, and assigns the result to $a.

$a .= $b appends $b to $a and assigns the result to $a.

$a ~= $b xor's $b and $a and assigns the result to $a.

As this is a relatively uncommon use, it maybe makes this interchange currently even harder to spot than later the use of =~ and ~=.


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Re^5: Thoughts on replacing -> with .
by Ralesk (Pilgrim) on Jun 12, 2013 at 11:38 UTC

    But XOR-assign is supposed to be $a ^= $b...

Re^5: Thoughts on replacing -> with .
by choroba (Canon) on Jun 12, 2013 at 11:38 UTC
    I am getting a syntax error for
    $a ~= $b
    لսႽ ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ

      Err - yes. I wonder how I came to this interpretation and I'm sorry I did not test it before...

      Correct. On the other hand, :$ ~= $b does work, but is has nothing to do with XOR.

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