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Re: In-place bitwise NOT?

by snoopy (Deacon)
on Jul 27, 2013 at 22:31 UTC ( #1046692=note: print w/replies, xml ) Need Help??


in reply to In-place bitwise NOT?

substr can be used as an lvalue:
my $bytes = length( $bits ); for (my $offset = 0; $offset < $bytes; $offset += 4096) { my $chunk = 4096; $chunk = $bytes - $offset if $offset + $bytes > $bytes; substr($bits, $offset, $bytes) = ~ substr($bits, $offset, $bytes); }

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Re^2: In-place bitwise NOT?
by BrowserUk (Pope) on Jul 27, 2013 at 22:51 UTC

    Indeed. See hdb's post.


    With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
    Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
    "Science is about questioning the status quo. Questioning authority".
    In the absence of evidence, opinion is indistinguishable from prejudice.

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