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Re: Console output != file output

by toolic (Bishop)
on Sep 01, 2013 at 17:53 UTC ( #1051836=note: print w/replies, xml ) Need Help??

in reply to Console output != file output

Tip #1 from the Basic debugging checklist: warnings

print() on closed filehandle FH at

You are opening the file for input, not output: see open. This works for me:

use warnings; use strict; my $type = 123; open (FH, '>out.txt'); print FH "start" . $type . "end"; close FH;

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Re^2: Console output != file output
by perlaintdead (Scribe) on Sep 02, 2013 at 15:09 UTC

    He should be doing 3 arg open and would be best if he change that file handle to a var. Just some best practices.

    use warnings; use strict; my $type = 123; my $FH; open ($FH, '>', 'out.txt'); print $FH ("start" . $type . "end"); close $FH;

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