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Re: extract file name from path

by keszler (Priest)
on Sep 11, 2013 at 16:50 UTC ( #1053525=note: print w/replies, xml ) Need Help??


in reply to extract file name from path

my $line = "root 30145 1 0 Jan30 ? 00:09:01 /root/java/app/java_app_1R +ule_java_app_2Rule.java --javaproc"; $line =~ m{.*/([^ ]+)}; # update - fixed typo of '/' to close regex my $id = $1;
perlretut

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[marinersk]: That seems a bit harsh. A newspaper deletes a picture and you respond by deleting a whole city?
[LanX]: yep
[Corion]: First he deleted Bielefeld, now he threatens to delete Darmstadt!
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[Corion]: People claim that Bielefeld exists, but that's just a ploy to hide LanX's acts!

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