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Re: extract file name from path

by keszler (Priest)
on Sep 11, 2013 at 16:50 UTC ( #1053525=note: print w/ replies, xml ) Need Help??


in reply to extract file name from path

my $line = "root 30145 1 0 Jan30 ? 00:09:01 /root/java/app/java_app_1R +ule_java_app_2Rule.java --javaproc"; $line =~ m{.*/([^ ]+)}; # update - fixed typo of '/' to close regex my $id = $1;
perlretut


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