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Re: s/this/$that/ Gives Variable Name, Not Contents of Variable

by Corion (Pope)
on Oct 07, 2013 at 15:27 UTC ( #1057268=note: print w/replies, xml ) Need Help??

in reply to s/this/$that/ Gives Variable Name, Not Contents of Variable

I can't reproduce that:

my $foo = "stuff"; @data = <DATA>; foreach (@data) { s/XXYY/$foo/; print; } __DATA__ <XXYY> XXYY XXYY test

gives the following output:

>perl -w <stuff> stuff XXYY test

Maybe you are looking at the wrong output file?

In any case, you most likely want a /g at the end of your substitution, so that the second input line becomes stuff stuff on output.

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