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Re: Re: Problems with regex grouping

by damian1301 (Curate)
on Aug 17, 2001 at 21:59 UTC ( #105755=note: print w/replies, xml ) Need Help??


in reply to Re: Problems with regex grouping
in thread Problems with regex grouping

To avoid throwing stuff in $1 when you don't need to, there is a great feature called clustering in REs with the (?:stuff here) stuff :). Just change
/<a href="(mailto:)?([^"]*)">([^<"]*)<\/a>/g
to

/<a href="(?:mailto:)?([^"]*)">([^<"]*)<\/a>/g

And that way nothing will be put in $1.

You may also want to consider chomping  $2 and $3 because a newline could get in there somewhere and cause some trouble.

Hope I helped out. :):):) Later

$_.=($=+(6<<1));print(chr(my$a=$_));$^H=$_+$_;$_=$^H; print chr($_-39); # Easy but its ok.

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[1nickt]: folks, would you say that 1.0 is an integer ?
[Lady_Aleena]: 1nickt, I wouldn't, but I'm not normal.
LanX aggrees, LA isn't normal ;-P
[Lady_Aleena]: LanX, thanks bunches.
[Lady_Aleena]: Rigth now I'm ranting in my head about an old subject.
[1nickt]: Hm, that is, how to prevent Perl from turning 1.0 into 1? I feel sure this must be an faq, but am reading perlnum and not finding the answer ...
[Lady_Aleena]: 1nickt, why does it matter in this case?
[1nickt]: Hm, perhaps this? "Operators which expect an integer force the argument into the integer format."
[1nickt]: Can this be? So print
[1nickt]: ... "expects an integer" ?

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