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Re: Regex problem - (non)greedy?

by ikegami (Pope)
on Nov 14, 2013 at 14:18 UTC ( #1062589=note: print w/ replies, xml ) Need Help??


in reply to Regex problem - (non)greedy?

Why do matches aginst (.*) and (.*?) result in exactly the same result?

Because there's only one ghi.

... /c/ matches "c" (at position 3) /d/ matches "d" /.*/ matches " cd EF ghi jkl" /g/ fails -> backtrack /.*/ matches " cd EF ghi jk" /g/ fails -> backtrack /.*/ matches " cd EF ghi j" /g/ fails -> backtrack ... /.*/ matches " cd EF " /g/ matches "g" /h/ matches "h" /i/ matches "i" -> success
... /c/ matches "c" (at position 3) /d/ matches "d" /.*?/ matches "" /g/ fails -> backtrack /.*?/ matches " " /g/ fails -> backtrack /.*?/ matches " c" /g/ fails -> backtrack ... /.*?/ matches " cd EF " /g/ matches "g" /h/ matches "h" /i/ matches "i" -> success

What needs to be done to get only the "EF" as a result?

(?s:(?!STRING).)* is to STRING as [^CHAR]* is to CHAR.

/cd(?:(?!cd|ghi).)ghi/s

Note: Unlike the trick of adding ^.* to the start of the pattern, this pattern can be used in other patterns.

Note: I think want "EF" instead of " EF ", but it's easier just to trim the whitespaces afterwards.


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