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Re: Replacing a list with one variable

by hdb (Parson)
on Nov 21, 2013 at 10:14 UTC ( #1063707=note: print w/ replies, xml ) Need Help??


in reply to Replacing a list with one variable

It seems that the IDs parameter requires a reference to an array so you need to split your string $bookIDList into an array, the brackets will then turn that into a reference:

my $bookIDList = "abc,ghj,zxc,bnm,qwe,rty,iop,sdf,ert"; my $param = { IDs => [ split /,/, $bookIDList ], sort => "AUTHOR", maxResults => 100 };

or you build a list in the first place and feed a reference to that list:

my @bookIDList = ( "abc", "ghj", "zxc", "bnm", "qwe", "rty", "iop", "s +df", "ert" ); my $param = { IDs => \@bookIDList, sort => "AUTHOR", maxResults => 100 };


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Re^2: Replacing a list with one variable
by Anonymous Monk on Nov 21, 2013 at 10:25 UTC

    Brilliant, that worked.
    Thank you

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