Right, it's just that the following is a bit confusing:
@b = (1..3)[3, 4]; # "empty" slice of a non-empty list;
# @b is empty, which is fine
@b = (1..3)[2, 3]; # the slice is "half empty",
# and yet @b now has TWO elements, not one
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I understand you find it confusing, but there is a valid reason for it.The basic principle is that you get a slice of exactly the length you asked it to be, padded with undefs if necessary, UNLESS the whole slice would have to be padded with undefs, in which case you get an empty list which is FALSE in any boolean test. Actually it is a clear application of the principle of least surprise: - It is the simplest way to distinguish between a slice from an empty list and a slice of a list of undefs. The former is FALSE, the latter is TRUE in a test.
- The slice returns you exactly the number of elements you asked it to return, not some unexpected or unpredictable smaller number.
Sometimes I like to think that the authors of Perl have thought long and hard and deep about all these issues. It is a comforting thought.
CountZero A program should be light and agile, its subroutines connected like a string of pearls. The spirit and intent of the program should be retained throughout. There should be neither too little or too much, neither needless loops nor useless variables, neither lack of structure nor overwhelming rigidity." - The Tao of Programming, 4.1 - Geoffrey James My blog: Imperial Deltronics
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It is the simplest way to distinguish between a slice from an empty list and a slice of a list of undefs. The former is FALSE, the latter is TRUE in a test.
Okay.
The slice returns you exactly the number of elements you asked it to return, not some unexpected or unpredictable smaller number.
False. You do get a smaller number of elements, i.e. 0, when all the slice indexes are beyond the end...as you pointed out:
...UNLESS the whole slice would have to be padded with undefs, in which case you get an empty list
So I think your first point is the only valid reason.
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