Re^2: (Beginner) Can 'qw' be implemented into a list?

[AnomalousMonk]

... a list is an UNordered sequence of values. ... Lists cannot be accessed using an index.

I disagree with both these assertions. To my way of thinking, lists are most certainly ordered. In what sense do you think of them otherwise? They can also be array indexed:

c:\@Work\Perl>perl -wMstrict -le
"my $s = ('foo', 'bar', 'baz')[1];
 print qq{'$s'};
 ;;
 $s = (qw(zip zap zop))[1];
 print qq{'$s'};
 ;;
 $s = qw(hic hac hoc)[1];
 print qq{'$s'};
"
'bar'
'zap'
'hac'

Note: I think the  qw(hic hac hoc)[1] example relies on a syntactic feature that, if not deprecated, is at least disparaged and contumed, and may be slated to go away someday/someversion (I'm running this with 5.14). It is certainly deprecated (as of 5.14) in a for-loop:

c:\@Work\Perl>perl -wMstrict -le
"for my $s qw(hic hac hoc) {
   print qq{'$s'};
   }
"
Use of qw(...) as parentheses is deprecated at -e line 1.
'hic'
'hac'
'hoc'

[Discipulus]

You are obviously right, thanks to point me in the right direction. I still find difficult to be precise describing Perl behaviour. My attempt was to tell the difference between lists and arrays and the OP confusion undeerstanding the @arr = qw (a b); construct.

Anyway you too are wrong, because the latin demonstrative pronouns are: qw(hic haec hoc) and not qw(hic hac hoc) ...;=)

L*

[AnomalousMonk]

A little hiccup in my Latin lexicon. :)