Hi Monk,
I love perl6 number, it use rationals number by defulat.
But how about large number? can I use it by default?
some code like that:
my Rat @example = 1 , * ** 0.9999 ... Inf;
This work fine on @example[^4]
But when the number going bigger , it will stored float point by default and type check fail.
How can i fix that?
fixed question: Addition 、 Subtraction 、Multiplication 、 Division 、 Modulo
Why?
How to fix it?
But how about large number? can I use it by default?
some code like that:
my Rat @example = 1 , * ** 0.9999 ... Inf;
This work fine on @example[^4]
But when the number going bigger , it will stored float point by default and type check fail.
How can i fix that?
fixed question: Addition 、 Subtraction 、Multiplication 、 Division 、 Modulo
This try will fail in Multiplication and Divisionmy Rat @ex01 = 1.0 , * + 0.9999 ... Inf; my Rat @ex02 = 1.0 , *  0.9999 ... Inf; my Rat @ex03 = 1.0 , * * 0.9999 ... Inf; my Rat @ex04 = 1.0 , * / 0.9999 ... Inf; my Rat @ex05 = 1.0 , * % 0.9999 ... Inf; my %ex = :add(@ex01), :substrat(@ex02), :mult(@ex03), div(@ex04), mod(@ex05); try { for < add substrat mult div mod > > $op { for 1 .. 20 > $count { .say; (%ex{$op})[$count] } } }
Why?
How to fix it?


Replies are listed 'Best First'.  

Re: perl6 rational number problem
by NetWallah (Canon) on Nov 21, 2017 at 05:42 UTC  
by freakcoco (Acolyte) on Nov 21, 2017 at 15:49 UTC  
by Anonymous Monk on Nov 21, 2017 at 18:07 UTC  
Re: perl6 rational number problem
by Anonymous Monk on Nov 21, 2017 at 08:55 UTC 
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