Re: '%hash = ()' is slower than 'undef %hash'

[kcott]

G'day rsFalse,

"What is your opinion?"

Unfortunately, you've provided very little information upon which an opinion might be based. Answers to the following would have been useful in your OP.

• How did you declare %hash? my? our? no strict 'vars'; and just let it pop into existence? something else?
• In what context are you using %hash?
• Why are you attempting to get rid of its contents (with undef or =())?
• Where's your benchmark code?
• Where's your benchmark results? [Sorry, but just saying "%hash = () is slower than undef %hash about 1.2 times" is not sufficient.]

Given all those unknowns, my opinion is that you should consider code like this:

{
    my %hash = (...);
    # operations on %hash here
}
# %hash doesn't exist here. Does that solve your problem?

Of course, with some answers to those questions, a better response might be forthcoming.