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(RhetTbull) Re: Arithmatic operation in PERL

by RhetTbull (Curate)
on Nov 19, 2001 at 23:10 UTC ( #126345=note: print w/replies, xml ) Need Help??

in reply to Arithmatic operation in PERL

The other examples listed here certainly work fine but since there's more than one way to do it, here's mine. I avoid slurping the file since I prefer to read in a line at a time if I don't know how big the input is going to be. If your input file is very large then slurping could use up quite a lot of memory. Also, my solution works regardless of the number of lines of numbers following each data record.
#!/usr/bin/perl use strict; use warnings; #print header line for output table print "Movie\t\tShow\t\tCollection>20\n"; LINE: while(<DATA>) { chomp; #find the record header next LINE if not /Movie="(\w+)"\s+show=(\d+)/; my ($movie,$show) = ($1,$2); my @numbers = (); while (($_ = <DATA>) =~ /\d+\s+\d+/) { chomp; push @numbers, (split " "); } #filter out just the numbers >= 20 @numbers = grep {$_ >= 20} @numbers; #add up the numbers my $total = 0; $total += $_ foreach @numbers; print "$movie\t\t$show\t\t$total\n"; } __DATA__ * Movie="ABC" show=4 10 20 30 14 90 30 21 13 11 10 09 23 22 05 22 15 19 20 * Movie="XYZ" show=4 10 20 30 14 90 30 21 13 11 10 09 23 22 05 22 15 19 10
Note that my solution produces different output than your example. You only count one occurrence of "22" on the last line but there are two. Is this by design? If so, you'd need to add a check to remove duplicate numbers (see How can I extract just the unique elements of an array? in perlfaq4).

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[choroba]: ovedpo15 Hard to tell without context. You probalby used $dir outside of its scope, which is the body of the "unless".
[choroba]: if you use unless as a statement modifier, you can't use the variable declared in the modifier in the statement.

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