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Linked List Strangeness

by Mandor (Pilgrim)
on Jan 31, 2002 at 17:25 UTC ( #142460=perlquestion: print w/ replies, xml ) Need Help??
Mandor has asked for the wisdom of the Perl Monks concerning the following question:

Since we've been doing linked lists in computer science
class recently but are unfortunately using the ol' Pascal
(which I've grown to dislike) I decided to code the same
simple program we finished in class - this time in Perl to see how it works.
After reading a little on that topic I made an implementation
like this :
use strict; my $list = undef; my $lastnode = \$list; while (1) { print '<i>nput, <o>utput : '; chomp (my $input = <STDIN>); if ($input eq 'i') { ($list, $lastnode) = add ($list, $lastnode); next; } if ($input eq 'o') { show ($list); next; } } sub add { my ($list, $lastnode) = @_; chomp (my $input = <STDIN>); my $newnode = [undef, $input]; $$lastnode = $newnode; $lastnode = \$newnode -> [0]; return ($list, $lastnode); } sub show { my $list = shift; for (my $node = $list; $node; $node = $node -> [0]) { print $node -> [1] . "\n"; } }
Interestingly I found out that this wasn't working.
Debugging it with Komodo 1.1 I found that after
$$lastnode = $newnode;
$list wasn't being set, which kinda defeated it's purpose.
Then I changed the implementation to this :
use strict; my $list = undef; my $lastnode = \$list; while (1) { print '<i>nput, <o>utput : '; chomp (my $input = <STDIN>); if ($input eq 'i') { &add; next; } if ($input eq 'o') { &show; next; } } sub add { chomp (my $input = <STDIN>); my $newnode = [undef, $input]; $$lastnode = $newnode; $lastnode = \$newnode -> [0]; } sub show { for (my $node = $list; $node; $node = $node -> [0]) { print $node -> [1] . "\n"; } }
I removed the variable passing and accessed $list and $lastnode directly.
And well, now it worked. But I don't get why passing the variable
makes example 1 don't work.

I am thankful for enlightenment.

Comment on Linked List Strangeness
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(tye)Re: Linked List Strangeness
by tye (Cardinal) on Jan 31, 2002 at 17:55 UTC

    Let me make a tiny change so that I can talk about this more easily. The problem is that one $list is being changed while the other $list isn't. So lets rename one of them:

    use strict; my $list = { head=>undef, tail=>undef }; while (1) { print '<i>nput, <o>utput : '; chomp (my $input = <STDIN>); if ($input eq 'i') { add($list); next; } if ($input eq 'o') { show($list); next; } } sub add { my ($list) = @_; chomp (my $input = <STDIN>); my $newnode = [undef, $input]; $list{tail}[0]= $newnode; $list{tail}= $newnode; }
    The problem is that $list is updated when you modify $$lastnode, but my ($root, $lastnode) = @_; makes $root a copy of $list and so $root is not changed. Then add() returns $root and, in effect, you end up doing $list= $root, which restores $list to its previous value.

    You could change the last line of add() to be return ($_[0], $lastnode); since $_[0] is an alias to $list and not a copy of $list.

    But better would be to encapsulate the $list and $lastnode variables into a single item that is passed to add() and show().

            - tye (but my friends call me "Tye")

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