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Re: Re: Re^2: On sushi

by shrubbery (Acolyte)
on Jun 25, 2002 at 19:40 UTC ( #177185=note: print w/replies, xml ) Need Help??


in reply to Re: Re^2: On sushi
in thread On sushi:

Not to rain on your parade, but here in the new york metro area, alot of the sushi chefs who dont seem to speak english are Chinese and not japanese. In fact, alot of the japanese restaurants are chinese owned. Enterprising lads aren't they :)

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Re: Re: Re: Re^2: On sushi
by snafu (Chaplain) on Jun 25, 2002 at 19:46 UTC
    No no...I know you are right. I know that the chefs I have mentioned are indeed Japanese. And, yes! Those Chinese dudes are quite enterprising! =P

    _ _ _ _ _ _ _ _ _ _
    - Jim
    Insert clever comment here...

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[Eily]: you could tie a variable into not having the same value each time, if you like to make people who try to debug your code facepalm
[Corion]: perl -wle 'package o; use overload q("") => sub {warn "str"; ""}, bool => sub{warn "bool"; 1}; package main; my $o={}; bless $o => o; print "Yay" if ($o && !length($o))'
[Corion]: But people writing such code should document the objects they construct and why it makes sense for an object to be invisible as string while being true in a boolean context
[hippo]: That's equal parts clever and horrendous.
[Eily]: the overload version wouldn't return true with "$x" && !length $x though, I guess
[hippo]: The more I look at this code, the more $x is a plain old scalar and the more this condition will never be true. I'm calling it a bug at this point.
[hippo]: Thanks for your input which has soothed my sanity (a little)
[Corion]: Eily: Sure - if you force both things into stringy things, then you break that magic. But that would also mean that you changed the expression, as now $x = 0.00 will be true instead of false as it were before
[Corion]: Ah no, at least in my feeble experiments that doesn't change the meaning
[Corion]: We sell sanity in small packages ;)

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