$new = param('home'); Now I wanna check to see if new has a / at the end

if ($new !~ m[/$]) {
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if it doesnt then add a /.

    $new .= '/';
}
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But it's a url so what if the user uses a \ instead of /.

URLs use slashes, not backslashes.

By the way: $new =~ s[\z(?<!/)][/];.

- Yes, I reinvent wheels.
- Spam: Visit eurotraQ.

$new =~ s/([^\/])$/$1\//;
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-caedes

Does file://c:\ qualify as a url?

Good question...

-caedes

since file url's (like file://c:\test) also work with forward slashses instead of backslashes (file://c:/test/), how about simply replacing all backslashes with a forward slash, and then use the same regex that has been provided by caedes:

$new =~ s/\\/\//g;
$new =~ s/([^\/])$/$1\//;
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Everyone has advised you to use a regex so far. However, when you know the position in the string to check for, substr is often a better method, as it is clearer and potentially has a lower overhead.

$new .= '/' unless substr $new, -1 eq '/';
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Light a man a fire, he's warm for a day. Catch a man on fire, and he's warm for the rest of his life. - Terry Pratchet

$new .= '/' unless substr $new, -1 eq '/'; can someone explain what -1 does

see perlman:perlfunc

# 1st argument given: string to process
# 2nd argument given: offset
# so here it means regardless of the true length the 
# last character in the string
substr ($new, -1);
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Have a nice day
All decision is left to your taste

thor