Simple log parser

[Anonymous Monk]

Hi Monks,

I have a log of working hours which I'd like to parse. The idea is that I calculate the net hours I've done from this file and insert these values into a MySQL db. The log file has the following format (one entry per line):

dd-mm-yy hh:mm am-dd-mm-yy hh:mm pm

I've been using the regex below to pull out all the values (which works fine) and work out the hours. The one small hitch is that I need to convert pm hours into 24h format for the calculation to work (i.e. 3pm should become 15h). I've tried to do this with a conditional but cannot get it to evaluate properly - all times, regardless if am or pm, get converted to 24h format.

@lines = <LOGFILE>;

foreach $line (@lines) {
if ($line != m/\s/) {
# regex to turn dates into epoch
($dd, $mm, $yy, $hh, $mt, $tt, $tdd, $tmm, $tyy, $thh, $tmt, $ttt) = $
+line =~ /(\d+)-(\d+)-(\d+)\s(\d+):(\d+)\s(am|pm)-(\d+)-(\d+)-(\d+)\s(
+\d+):(\d+)\s(am|pm)/;

if ($tt == 'pm') {
$hh = $hh + 12;
}

if ($ttt == 'pm') {
$thh = $thh + 12;
}

$t_from = timelocal(0,$mt,$hh,$dd,$mm,$yy);
$t_to = timelocal(0,$tmt,$thh,$tdd,$tmm,$tyy);
$s_elapsed = $t_to - $t_from;

...

I'm guessing that this is one of those extremely simple problems - I just can't see where I'm going wrong. Any help would be greatly appreciated!

Mark