|Perl: the Markov chain saw|
No choiceby Anonymous Monk
|on Jan 08, 2003 at 00:42 UTC||Need Help??|
OK, we'll start by eliminating "No correct choice", since if that's the correct choice, it isn't.
"All of the above" would mean there's both no choice, one choice, and more than once choice.. all at the same time. This is obviously impossible.
If "None of the above" is the correct choice, then either there's one correct choice or more than one, which means that some of the above would be true.
"Such silly choices that I'm not voting on it".. you're voting to say that you will not vote on it? Just as wrong as the others.
That leaves the top three ones.
Now, if the top one is true, then there is only one choice, which must be the top one. However the second one is then also true, and that's a contradiction.
That leaves one choice.. which says that there is more than one choice, which isn't so.
That leaves no correct choices.. which would mean the fourth choice is correct, which isn't so.
Hmm.. conclusion: the given problem is self-contradictory.
(damn, I must be bored to be typing this)