"be consistent"  
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Re: An informal introduction to O(N) notationby BUU (Prior) 
on Jan 18, 2003 at 05:26 UTC ( #227926=note: print w/replies, xml )  Need Help?? 
O(N2) says that the algorithm's performance is proportional to the square of the data set size. This happens when the algorithm processes each element of a set, and that processing requires another pass through the set. The infamous Bubble Sort is O(N^{2}). Shouldn't bubble sort be O(N^{N}) as you might have to process the entire thing once for each element, if it was sorted backwords for example?
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