Re: local element of my() array????

[BrowserUk]

This demonstrates that your interpretation is correct...

#! perl -slw
use strict;

my @foo = 1..9;
{
    local $foo[3] = 'modified';
    print "@foo";
}
print "@foo";
__END__
C:\test>temp
1 2 3 modified 5 6 7 8 9
1 2 3 4 5 6 7 8 9

...now what's the problem:).

It's really quite clever and very useful in a few situations.

---

Examine what is said, not who speaks.

The 7th Rule of perl club is -- pearl clubs are easily damaged. Use a diamond club instead.

[Anonymous Monk]

My only problem is a lack of full understanding. If I only sort of think I get it, I'll screw something up. :)

For example, I can't say

  my @x;
  local @x;

because local requires a package variable such as @::x to localize, and my @x isn't in any package, because it's lexical. But I *can* say

  my @x;
  local $x[0];

What's going on there? I just need an explanation of the magic that's handling that, because otherwise I have no clue what's happening, and the world becomes a dark and mysterious place. :)