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Re: Re: quick question about hash element access

by Chmrr (Vicar)
on Jun 28, 2003 at 01:11 UTC ( #269787=note: print w/replies, xml ) Need Help??


in reply to Re: quick question about hash element access
in thread quick question about hash element access

And with very few changes you can make it an lvalue, so you can use it to assign to:

sub nested : lvalue { @_ == 1 ? $_[0] : nested($_[0]{$_[1]}, @_[2..$#_]); }

..and now you can say:

nested(\%hash, a => b => c =>) = "VALUE";

TThis can lead to such fun looking constructs as nested $hashref, a => b => c => d => = 42; Note that this code will only work under perl 5.6.0 or later, though; earlier perls had more restricted definitions of lvalues. See also descending a tree of hash references.

perl -pe '"I lo*`+$^X$\"$]!$/"=~m%(.*)%s;$_=$1;y^`+*^e v^#$&V"+@( NO CARRIER'

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[PriNet]: i guess i'll just have to use two seperate hashes, there are two, but one is larger than the other, and when i reference the smaller one, it holds onto the values that were assigned to the larger hash (the keynames change, but unless i reassign a new valu

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