in reply to bitwise string operator question
Hi all.
Abigail++ (very cool).
Background:
& = bitwise 'and'
| = bitwise 'or'
^ = bitwise 'xor'
The bitwise xor operator only returns '1' when *one* of the operands is different (e.g. 0 ^ 1, 1 ^ 0). If both operands are the same, the result is '0'.
In ACSII, in order to quickly move from uppercase to lowercase (or vice versa), simply add / subtract 32 from the number respectively. The 'space' character, incidentally, has an ASCII value of 32.
Example:
A = 65
a = 97 (65+32 = 97) and (97-32=65).
Hope this helps, Anonymous Monk.
-Katie
Abigail++ (very cool).
Background:
& = bitwise 'and'
| = bitwise 'or'
^ = bitwise 'xor'
The bitwise xor operator only returns '1' when *one* of the operands is different (e.g. 0 ^ 1, 1 ^ 0). If both operands are the same, the result is '0'.
In ACSII, in order to quickly move from uppercase to lowercase (or vice versa), simply add / subtract 32 from the number respectively. The 'space' character, incidentally, has an ASCII value of 32.
Example:
A = 65
a = 97 (65+32 = 97) and (97-32=65).
Hope this helps, Anonymous Monk.
-Katie
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