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by pete (Novice)
on Aug 18, 2000 at 05:30 UTC ( #28412=obfuscated: print w/replies, xml ) Need Help??

perl -M5.6.0 -MLWP::Simple -e '*_ = do { +6}; _ ( q-0201.026.0261.064- . +7.55.48. . . +.54.98)'
perl -e 's,, Another Perl ,,*"=*`,m,$,,print "@{[Just => Hacker]}"'

Replies are listed 'Best First'.
by Adam (Vicar) on Aug 18, 2000 at 22:59 UTC
    I actually voted for this because I liked the .sig <grin>
    I'm not so sure that obfuscatations should use libraries... even LWP::Simple.
      i consider Abigail's JAPH's to be the model for good JAPHing. in one of her well known ones she uses Math::BigInt. (as in this clpm post) Therefore pulling in a module is fair game. I went to her JAPH talk at YAPC 19100 and she gave these rules for JAPH's (which i hold to except on rare occasion) 1. short (preferably 4x80 chars or less).
      2. prints "Just Another Perl Hacker"
      I broke the 2nd, but its a clue :)
      perl -i -pe 'splice @a,rand $.,0,$_}for (@a){' #disorder file
        Fair enough. (I did, after all, vote ++ for your post.)
        Its a shame Abigail stoped coming to this site. She had some great posts.

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[Corion]: Aaah - you should be able to do this with overload, but I would hit somebody really hard if they constructed objects that are true but the empty string, and you not knowing about the domain knowledge where this makes sense
[Eily]: you could tie a variable into not having the same value each time, if you like to make people who try to debug your code facepalm
[Corion]: perl -wle 'package o; use overload q("") => sub {warn "str"; ""}, bool => sub{warn "bool"; 1}; package main; my $o={}; bless $o => o; print "Yay" if ($o && !length($o))'
[Corion]: But people writing such code should document the objects they construct and why it makes sense for an object to be invisible as string while being true in a boolean context
[hippo]: That's equal parts clever and horrendous.
[Eily]: the overload version wouldn't return true with "$x" && !length $x though, I guess
[hippo]: The more I look at this code, the more $x is a plain old scalar and the more this condition will never be true. I'm calling it a bug at this point.
[hippo]: Thanks for your input which has soothed my sanity (a little)
[Corion]: Eily: Sure - if you force both things into stringy things, then you break that magic. But that would also mean that you changed the expression, as now $x = 0.00 will be true instead of false as it were before
[Corion]: Ah no, at least in my feeble experiments that doesn't change the meaning

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