Puzzled over 'my'

I was trying to use grep in a scalar context, and thought this would work:

my($ok) = grep {/Some String/} @anArray;
[download]

But this just returned "Some String" rather than a number. If I remove 'my', the code works as I expected. This has upset my mental picture of what 'my' actually does. Please can anybody point me at a good resource to explain the subtleties if 'my'? Many thanks, Myomancer

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Re: Puzzled over 'my' by shenme (Priest) on Oct 23, 2003 at 12:50 UTC
Change it to `my $ok = grep {/Some String/} @anArray;` [download] and you'll go back to scalar context. Using the parentheses forced the matches into array context.	[reply] [d/l]
Re: Puzzled over 'my' by Anonymous Monk on Oct 23, 2003 at 12:53 UTC
This is list context. `my($ok) = grep {/Some String/} @anArray;` [download] This is scalar context `my $ok = grep {/Some String/} @anArray;` [download]	[reply] [d/l] [select]
Re: Puzzled over 'my' by tadman (Prior) on Oct 23, 2003 at 20:47 UTC
You must've not only removed the `my`, but the brackets as well. It was the brackets, mind you, that are the key here. Including brackets means that you're assigning a list to a list, in this case, the result of the `grep` operation into a list containing the variable `$ok`. Thus, the first thing grepped goes into the first variable, and you get "Some String". If you want to know how many things you got, you need to force a list to scalar conversion. That might sound fancy, but it's just a way of saying you want to assign the list directly to the variable instead of to a list of variables. No brackets. If you're a bit fuzzy, here's some examples; `my @list = ("A","B","C"); my ($var) = @list; # $var becomes "A" my $var = @list; # $var becomes 3 my ($var) = scalar(@list); # $var becomes 3 my $var = scalar(@list); # $var becomes 3 (same idea)` [download]	[reply] [d/l]


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Puzzled over 'my'

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