Building scalar from File::Findby sunadmn (Curate)
|on Dec 29, 2003 at 19:18 UTC||Need Help??|
sunadmn has asked for the
wisdom of the Perl Monks concerning the following question:
Good day fellow monks I have the below code and have a it working for the most part but one issue I have ran into is when I build $out if there is not seven dirs I get output that looks like so:
Now the issue I would like to resolve is how can I build my $out scalar so that it will grab anything from dir 4 on and build itself from that,so if I have a file living under /net it will build $out like somedomain.net and if I have something like /us/pa/k12 it will look like somadomain.k12.pa.us and with either I wont have the trailing "." after the name if it doesn't equal seven in length. Any help you may all point out to me would be great as I am pulling my hair out trying to figure this one out right now.