I think what is being overlooked is the effect of evaluating the empty statement block {}, which appears in all of the examples of the OP.
In the statement if ('') {}, the last expression evaluated is the conditional, which is false (the empty string); this is the value returned.
In the statement if ('true') {}, the last expression evaluated is the true clause, which is the empty statement block, which evaluates to the empty string; this is the value returned.
In the statement if (! 'true') {}, the last expression evaluated is the conditional, which evaluates to false (the empty string), etc.
This can be confirmed by re-writing the if statement to the 'statement modifier' form and using do {} for the empty statement (because {} on its own will be interpreted as an anonymous hash constructor).
E.g.:
C:\@Work\Perl>perl -wMstrict -e "sub S { if (! $_[0]) {} }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<>
<>
C:\@Work\Perl>perl -wMstrict -e "sub S { if ( $_[0]) {} }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<>
<>
C:\@Work\Perl>perl -wMstrict -e "sub S { unless (! $_[0]) {} }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<1>
<>
C:\@Work\Perl>perl -wMstrict -e "sub S { unless ( $_[0]) {} }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<>
<hiya>
C:\@Work\Perl>perl -wMstrict -e "sub S { do {} if ! $_[0] }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<>
<>
C:\@Work\Perl>perl -wMstrict -e "sub S { do {} if $_[0] }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<>
<>
C:\@Work\Perl>perl -wMstrict -e "sub S { do {} unless ! $_[0] }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<1>
<>
C:\@Work\Perl>perl -wMstrict -e "sub S { do {} unless $_[0] }
print qq(<@{[ S($_) ]}> \n) for @ARGV" "" "hiya"
<>
<hiya>
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