I got this code from this article perl.com.
sub make_counter {
my $start = shift;
return sub { $start++ }
}
my $from_ten = make_counter(10);
my $from_three = make_counter(3);
print $from_ten->() . "\n";
print $from_ten->() . "\n";
print $from_three->() . "\n";
I tried to read the article on the explanation of the code above but I could not figure out how it is able to 'retain/remember' the old values.
Can someone further dissect or rewrite this code to show what is exactly happening?
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