No, the array is copied before the function returns. You can observe that:
You missed the point. It does not make any difference when the array is copied, before or after the return. The point was, when the function returns, the caller "can know" that some array was returned. So it makes difference what you return from the function, array or list or scalar.
If you just wanted to say, that the array seen by the caller is not the same object as the array that was given to "return", then you are absolutely correct. But this is true for any returned object. Even references to arrays are copied, they are not the same references as the returned variables. Of course they reference the same array, but they are not the same references. So arrays are not an exception to this rule. It is general feature of the language.
By the way, your code examples don't prove that the copying happens before the return. They just prove, that the "for" loop works with copies of values. Nothing else. When those copies were made stays unclear :)
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