In S02 synopsis, section "Names and Variables", I see:
$<foo> match variable, short for $/{'foo'}
So, when you say my $<-var>;, you are actually initializing the key -var of the hash $/.
Here's what I see in recent rakudo:
>> perl6 -v
This is Rakudo Perl 6, version 2011.07-2-g1b7dd12 built on parrot 3.6.
+0 RELEASE_3_6_0
>> perl6
> my $<-var> = 42
42
> $/
-var 42
> $/.WHAT
Hash()
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